The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
<em><u>Solution:</u></em>
Given the statement:
Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen
Let us first understand the given statement,
Let the number be "x"
" sum of a number and four" means x + 4
"Three sets of a sum of a number and four" translated to 3(x + 4)
"sum of seven times the same number and thirteen" means 7x + 13
<em><u>Thus the algebraic expression for given statement is:</u></em>
<em><u>Using distributive property in above expression</u></em>
Therefore,
<em><u>Combine the like terms</u></em>
Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
Answer:
3848,451001
Step-by-step explanation:
A = πr²
A = π[35]²
A = 1225π
A = 3848,451001
I hope this is correct, and as always, I am joyous to assist anyone at any time.
Answer:
d= 2√10
Step-by-step explanation:
y= 3x - 5
3x - y - 5=0
d= | 3* 7 +(-1) * (-4) + (+5) |
________________
d = | 20 | / 
d = 20 /
d = 2
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
Percent means per one-hundred...
(40/100)*(80/100)=3200/10000=32/100=32%
