Answer:
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
Step-by-step explanation:
Answer:
First of all what is a mathswatch second nice profile pic
I think it’s saying like is it a parallel or so
The total is 158 units
(3z+2)+(4z)+(3z+2)+(4z)=158
Combine like terms
14z+4=158
Subtract 4 from both sides
158-4=154
14z=154
Divide by 14 on both sides
154/14=11
z=11