1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Answer:
sounds like a relationship problem
Step-by-step explanation:
that cheating wont fix.
-6x-7+8=19 and then add your like terms so it’s -6x+1=19 and then subtract one on both sides so it’s -6x=18 so x=-3
-2/3x + 2.8 = -8.2 what is x
Add 2.8 on both side of the equation
-2/3x=-11
Divide both side by -2/3
x=33/2
Check: -2/3(33/2)+ 2.8 = -8.2
-11+2.8=-8.2
-8.2=-8.2
Answer is x=33/2
Find the vertex by using the formula -b/2a
To find a and b, we must know that a and b are located at y = ax^2 + bx + c.
We find that b is 4 and a is 1 by looking at the given quadratic function.
The answer is A. -4/2(1) because the question is looking for the correct steps to find the answer.
