Answer:
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Answer:
<em><u>=15a−8</u></em>
Step-by-step explanation:
Let's simplify step-by-step.
4(2a−1)−4+7a
Distribute:
=(4)(2a)+(4)(−1)+−4+7a
=8a+−4+−4+7a
Combine Like Terms:
=8a+−4+−4+7a
=(8a+7a)+(−4+−4)
=15a+−8
Answer:
=15a−8
hope i helped
-lvr
Answer:
15°
brainlest
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
<span>(-yx^2)^2 • -2x^0y^3
= x^4y^2 (-2y^3)
= - 2x^4y^5</span>
