Answer:
(5−6)2+(−15+12)2=(5−2)2+(−15+14)2
Step-by-step explanation:
Circle equation is : (x -h)^2 + (y - k)^2 = r^2
center (h, k) = (5, -15)
r = Distance from (5, -15) to point A (2, -14)
r = root ( (5 - 2)^2 + (-15 - (-14))^2 )
r = root ( 3^2 + 1^2)
r = root(10)
Equation is (x - 5)^2 + (y + 15)^2 = 10
Check point P(6, -12)
(6 - 5)^2 + ( (-12) + 15 )^2 check if this equals 10
1^2 + 3^2 = 1 + 9 = 10, 10 = 10 good
It is the same as using the equation:
(5−6)2+(−15+12)2=(5−2)2+(−15+14)2
Need more info to help you
<span>8 + 6 x 3 - (20/2)^2
</span><span>= 8 + 18 -(10)^2
</span>= 8 + 18 - 100
= -74
answer
- 74
Answer:5x
Step-by-step explanation:
Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:
Re-write 'em as a standard form:
So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:
And they do not have any collision point
