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2 years ago

Look at the diagram below of rectangle ABCD.

Mathematics

2 answers:

Alex17521 [72]2 years ago

7 0

Answer:

Igrtgr

Step-by-step explanation:

Druidcvjhdvdkfdtg

choli [55]2 years ago

6 0

Step-by-step explanation:

The statements which are true are

$ac \: = \sqrt{ {cd}^{2} + {ad}^{2} } \\ and \\ ac \: = \sqrt{ {ab}^{2} + {bc}^{2} }$

Hope it will help :)❤

You might be interested in

Find two consecutive numbers whose squares differ by 45

Wittaler [7]

Answer:

The 2 numbers are 22 and 23

Step-by-step explanation:

let the two numbers be x and x+1

according to the question:

(x+1)^2 - x^2 = 45

x^2+1+2x - x^2 = 45

2x + 1 = 45

2x= 44

x = 22

the other number is x+1 = 22+1 = 23

therefore, the two consecutive numbers are 22 and 23

Hope it helped u....

5 0

2 years ago

If g(x)= square root of 3-5x, find the domain of g'(x).

BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0

3 years ago

Read 2 more answers

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

3 years ago

Solve for x and y

bekas [8.4K]

Answer:

x = 2√2

y = 2√6

Step-by-step explanation:

Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)

These will be equal since the triangles are similar

shorter leg : longer leg

(blue triangle = red triangle)

⇒ x : 4 = 2 : x

⇒ x/4 = 2/x

⇒ x² = 8

⇒ x = √8

⇒ x = 2√2

Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.

Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)

⇒ 4² + (2√2)² = y²

⇒ y² = 24

⇒ y = √24

⇒ y = 2√6

7 0

2 years ago

Can someone please explain why 33 and 35 are these answers?

nordsb [41]

For #32,
P=2L+2W
Subtract 2W from both sides, and swap left and right
2L = P-2W
Divide by 2
2L/2=(P-2W)/2
L = P/2 - 2W/2
L=P/2 - W

For #35
Most of the expenses are in fractions (of the original amount, A), so they can be added:
A/4 + A/5 + 2A/5 + 750 = A
add the fractions, with a common denominator of 20,
5A/20 + 4A/20 + 8A/20 +750 = A
(5A+4A+8A)/20 +750 = A
17A/20 + 750 = A

Now subtract 17A/20 from both sides and swap left and right
A - 17A/20 = 750
(3/20)A = 750

Multiply both sides by 20/3 (to make one unit of A on the left)

(3/20)*(20/3) A = 750*20/3
A =250*20=5000

7 0

3 years ago