Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.
i.e. 

We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let
be the sample mean.
Formula : 
Then, the probability that the sample mean is at least $25.00 will be :-

Hence, the likelihood the sample mean is at least $25.00= 0.0170
Step 1: Flip the equation.
4.9p=44.1
Step 2: Divide both sides by 4.9.
4.9p= 44.1
4.9/4.9 = 44.1/4.9
p=9
The answer would be .0333 hope this helped
-17/15
Find a common denominator, and multiply the numerator by the same factor. Don't forget that adding a negative is really subtracting.