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3 years ago

Please help!!! Find the domain of the function y = 2 cot(5∕8x).

Mathematics

1 answer:

Elza [17]3 years ago

4 0

Answer:

Function

Step-by-step explanation:

) Domain is defined as the set of possible values of x where function is defined.

For domain,

So,

The value of x is define as

The domain of the function is all real numbers except

The range is defined as all the y values for every x.

So, The range of the function is all real numbers.

2) The general form of the cot function is

Where, Period is

On comparing, B=3

So, The period of the given function is

3) Vertical asymptote is defined as the line which approaches to infinity but never touches the line.

The vertical asymptote is at where function is not defined.

The two vertical asymptote is

Put n=0,

Put n=1,

So, The two vertical asymptote are

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8 0

3 years ago

Read 2 more answers

What number best completes both equations? 5/7÷1/3=? ?×1/3=5/7

Nat2105 [25]

Consider the given equations:

The first equation is as:

$\frac{5}{7} \div \frac{1}{3} = ?$

So, $\frac{5}{7} \div \frac{1}{3}$

= $\frac{5}{7} \times \frac{3}{1}$

Multiplying the given fractions, we get as

= $\frac{15}{7}$

Now, consider the second equation as:

$? \times \frac{1}{3} = \frac{5}{7}$

Multiplying by '3' to both the sides of the equation, we get

$? \times \frac{1}{3} \times 3 = 3 \times \frac{5}{7}$

$? = \frac{15}{7}$

So, the number which best completes both the equations is $\frac{15}{7}$ .

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3 years ago

Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given curves

Vadim26 [7]

The expression on the left side describes a parabola. Factorize it to determine where it crosses the y-axis (i.e. the line x = 0) :

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… = -3 (y - 1) (y - 2) = 0

⇒ y = 1 or y = 2

Also, complete the square to determine the vertex of the parabola:

-3y² + 9y - 6 = -3 (y² - 3y) - 6

… = -3 (y² - 3y + 9/4 - 9/4) - 6

… = -3 (y² - 2•3/2 y + (3/2)²) + 27/4 - 6

… = -3 (y - 3/2)² + 3/4

⇒ vertex at (x, y) = (3/4, 3/2)

I've attached a sketch of the curve along with one of the shells that make up the solid. For some value of x in the interval 0 ≤ x ≤ 3/4, each cylindrical shell has

radius = x

height = y⁺ - y⁻

where y⁺ refers to the half of the parabola above the line y = 3/2, and y⁻ is the lower half. These halves are functions of x that we obtain from its equation by solving for y :

x = -3y² + 9y - 6

x = -3 (y - 3/2)² + 3/4

x - 3/4 = -3 (y - 3/2)²

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± √(1/4 - x/3) = y - 3/2

y = 3/2 ± √(1/4 - x/3)

y⁺ and y⁻ are the solutions with the positive and negative square roots, respectively, so each shell has height

(3/2 + √(1/4 - x/3)) - (3/2 - √(1/4 - x/3)) = 2 √(1/4 - x/3)

Now set up the integral and compute the volume.

$\displaystyle 2\pi \int_{x=0}^{x=3/4} 2x \sqrt{\frac14 - \frac x3} \, dx$

Substitute u = 1/4 - x/3, so x = 3/4 - 3u and dx = -3 du.

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$\displaystyle 12\pi \left(\frac12 \left(\frac14\right)^{3/2} - \frac65\left(\frac14\right)^{5/2}\right) - 12\pi (0 - 0)$

$\displaystyle 12\pi \left(\frac1{16} - \frac3{80}\right) = \frac{12\pi}{40} = \boxed{\frac{3\pi}{10}}$

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2 years ago

A 25-ft ladder is leaning against a house, as shown in the picture. Find the slope of the ladder.

IgorC [24]

Answer:

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