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V125BC [204]
3 years ago
13

3. Which graph best represents the solution to the following system? (1 point) (5x – 2y <10

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

The graph in the attached figure

Step-by-step explanation:

The complete question is

Which graph best represents the solution to the following system?

5x - 2y < (less than or equal to) 10

x + y < 5

we have

5x-2y\leq 10 ----> inequality A

isolate the variable y

Adds 2y both sides

5x \leq 10+2y

Subtract 10 both sides

5x-10 \leq 2y

Divide by 2 both sides

2.5x-5 \leq y

Rewrite

y \geq 2.5x-5

The solution of the inequality A is the shaded area above the solid line

The equation of the solid line is y=2.5x-5

The slope of the solid line is positive m=2.5

The y-intercept of the solid line is (0,-5)

The x-intercept of the solid line is (2,0)

x+y < 5 -----> inequality B

Isolate the variable y

Subtract x both sides

y < -x+5

The solution of the inequality B is the shaded area below the dashed line

The equation of the dashed line is y=-x+5

The slope of the dashed line is negative m=-1

The y-intercept of the dashed line is (0,5)

The x-intercept of the dashed line is (5,0)

using a graphing tool

The solution of the system of inequalities is the shaded area between the solid line and the dashed line

see the attached figure

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Answer:

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Step-by-step explanation:

4n+n=5n

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Step-by-step explanation:

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the volume of a storage tub shaped like a rectangular prism is 24 ft cubed. The height of the top is 3 ft the width is W feet in
kondor19780726 [428]
<h2>Answer:</h2>

\boxed{W=2ft}

<h2>Step-by-step explanation:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. On the other hand, a rectangular prism is a solid whose base is a rectangle.  Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

V=L\times W\times H

From the statement of the problem we know:

V=24ft^3 \\ \\ H=3ft \\ \\ W=W \\ \\ L=W+2

So:

24=(W+2)(W)(3) \\ \\ 3W(W+2)=24 \\ \\ 3W^2+6W-24=0 \\ \\ From \ the \ Quadratic \ Formula: \\ \\ W_{12}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ W_{12}=\frac{-6 \pm \sqrt{6^2-4(3)(-24)}}{2(3)} \\ \\ W_{1}=2 \\ \\ W_{2}=-4

Since we can't have negative distance, the only valid option is \boxed{W=2ft}

3 0
3 years ago
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