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melomori [17]
2 years ago
5

If the radius of a sphere is halved, what happens to the volume of the sphere? Use your algebra skills to develop a formula for

the volume of the reduced sphere, V', in terms of V.
Mathematics
2 answers:
valkas [14]2 years ago
4 0
Since V = (4/3) * pi * R^3

If R is halved, V' will reduce by a ratio of (1/2)^3 = 1/8

So V' = (1/8)V
vlada-n [284]2 years ago
3 0

Answer:

Step-by-step explanation:

Given that the radius of a sphere originally r is halved.  We have to find the new volume of the sphere.

Volume of the sphere = \frac{4}{3} \pi r^3

When radius is halved new radius = r/2

Hence volume of the reduced sphere

=\frac{4}{3}\pi (\frac{r}{2} )^3=\frac{1}{8} \frac{4}{3}\pi r}^3\\=\frac{1}{8} V

Volume becomes 1/8 times of the original volume.

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Mary has 2 more video games than John. Together, they have 30 video games.
k0ka [10]

Answer: Mary has  16 video games.

Step-by-step explanation:

x+(x+2) =30

2x + 2 =30

       -2   -2

2x =28

x= 14  

(14+ 2) = 16

5 0
3 years ago
Read 2 more answers
Hello there, <br><br> can someone please help me with this question
monitta

Answer:

10 sides.

Step-by-step explanation:

Two same interior angles + 72 degrees = 360.

Thus, the interior angle of the polygon is \frac{360-72}{2} =144.

The formula to find the interior angle of a polygon is \frac{180(n-2)}{n}

\frac{180(n-2)}{n} =144

Multiply both sides by n:

\frac{180\left(n-2\right)}{n}n=144n

180\left(n-2\right)=144n

Expand:

180n-360=144n

Add 360 to both sides:

180n-360+360=144n+360

180n=144n+360

Subtract 144n from both sides:

180n-144n=144n+360-144n

36n=360

Divide both sides by 36:

\frac{36n}{36}=\frac{360}{36}

n=10

7 0
2 years ago
-3(4x+5) please help<br>​
Natasha_Volkova [10]
Answer:
-12x-15
explanation:
you multiply -3 by 4x, gives u -12x and then you multiply -3 by 15 which gives you -15
then you put it in an equation
-12x-15
7 0
2 years ago
Twelve people are given two identical speakers, which they are asked to listen to for differences, if any. Suppose that these pe
ruslelena [56]

Answer:

0.0537

Step-by-step explanation:

This follows a binomial distribution with : n

Number of trials 'N' = 12 ; Probability of success (difference between speakers) 'p' = 1/2 or 0.5 ; Probability of failure (no difference b/w speakers) = 1/2 or 0.5 ; No of success 'r' = 3

P (X = 3) = N C r. (p)^r.(q)^(n-r)\\

= 12C3 (0.5)^3 (0.5)^9

0.0537

7 0
3 years ago
The weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a s
Evgen [1.6K]

Answer:

209.005 gms

Step-by-step explanation:

Given that the weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a standard deviation of 3 grams.

Let X be the weight of packets of cookies produced by manufacturer

X is N(202, 3) gms.

To find the  weight that should be stamped on the packet so that only 1% of the packets are underweight

i.e. P(X<c) <0.01

From std normal table we find that z value = 2.335

Corresponding x value = 202+3(2.335)

=209.005 gms.

5 0
2 years ago
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