Complete Questions:
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.
a. 40
b. 48
c. 56
d. 64
Answer:
a. 0.35
b. 0.43
c. 0.49
d. 0.54
Step-by-step explanation:
(a)
The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.
Let s be the sample space of all integer not exceeding 40.
The total number of ways to select 6 numbers from 40 is
.
Let E be the event of selecting none of the correct six integers.
The total number of ways to select the 6 incorrect numbers from 34 numbers is:

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is


Therefore, the probability is 0.35
Check the attached files for additionals
Answer:

Step-by-step explanation:

6-3=3
2/8-5/8=3/8
you would have to change the denominator
Answer:
111 points
Step-by-step explanation:
First, thing I like to do is to convert word problems into an eqaution or write down the important information. So, Math = 37 points and now the points are tripled because of where she placed the word. Also, tripled is implying that her base score for the word is 3 times the original value.
So, 
= 111 points.
Answer:
First Step: separate x^2 from -16
Second Step: add -16/25 to the other side.
Step-by-step explanation:
x^2 - 16/25 = 0
^^ this might be easier if you separate x^2 and -16
<em>First Step-</em>
so rewrite the problem as x^2/25 -16/25 = 0
then...
<em>Second Step-</em>
add -16/25 to the other side. This makes it: x^2/25 = 16/25
<em>Continuation-</em>
Now, you can multiply 25 on both sides to cancel it out.
so you have x^2 = -16
Message me if you want to solve for x.