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trapecia [35]
3 years ago
9

Find the circumference of the circle. Use 3.14 for piπ. WILL MARK BRAINLIEST!!! ⭐️

Mathematics
2 answers:
timama [110]3 years ago
4 0
Ok so the circumference equation is

C=2piR
So insert

2(3.15)(11)

This makes your answer 69.11504
Kitty [74]3 years ago
3 0

Answer:

c=2πr

c= 2*π*11

c=6.28*11

c=69.08

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What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?
Nat2105 [25]
Hello :
f(-4) = 4(-4)+9 = -7
f(-2) = 4(-2)+9 = 1
f(0) = 4(0)+9 = 9
f(2) = 4(2)+9 = 17
the range of the function f(x) = 4x + 9 is : <span>D' = {-7, 1, 9, 17}</span>
8 0
3 years ago
Find the prime factorizations foor the following numbers 36 and 84
Varvara68 [4.7K]
Answer:

36 = 2² * 3²
84 = 2² * 3 * 7


Explanation:

Pf of 36 = 2 * 2 * 3 * 3 which then becomes 2 (to the power of 2) times 3 (to the power of 2)

Pf of 84 = 2 * 2 * 3 * 7 which then becomes 2 (to the power of 2) * 3 * 7

If this helps it would be greatly appreciated if you thanked me.
6 0
3 years ago
It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

  =\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

   = 8

Thus, the degrees of freedom of the test is 8.

8 0
3 years ago
The relative growth rate for a certain type of mutual fund is 15% per year. An account is opened with a balance of $3,000. How m
wlad13 [49]

We have been given that an account is opened with a balance of $3,000 and relative growth rate for a certain type of mutual fund is 15% per year.  

In order to tackle this problem we have to find the value of mutual fund after 5 years. For our purpose we will use compound interest formula.

A=P(1+r)^{t} ,where A= amount after t years, P= principal amount, r= interest rate (decimal) and t= number of years.

After substituting our given values in above formula we will get

A=3000(1+.15)^{5}

Now we will solve for A

A=3000(1+.15)^{5}=3000(1.15)^{5}\\ A=3000\cdot (2.011357187)=6034.07

Therefore, after 5 years mutual fund is worth $6034.07.


8 0
3 years ago
Can Someone help me in this?
My name is Ann [436]

Answer:

You should ask your teacher for help and pay attention in class

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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