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Aloiza [94]
3 years ago
5

Help ill reward brainest

Mathematics
1 answer:
inna [77]3 years ago
3 0
0.876 is your answer, because it rounds to 0.88 (88 hundredths)

As you know, the hundredths place is two numbers to the right of the decimal. And 4 & below in the next position round down, while 5 & up round up.

So number / rounded:

0.088 / 0.09
0.874 / 0.87
0.876 / 0.88
0.869 / 0.87
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The diagram compares the ratio of girls in the chorus to boys in the chorus. What is the ratio of girls to boys? If there are 60
Ray Of Light [21]
You need to show the diagram too
8 0
3 years ago
Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

5 0
4 years ago
I don't understand what I'm doing wrong, please help​
VashaNatasha [74]

Answer:

dy/dx= 7- 3x^-1/2

when X=1

dy/dx = 4

as it is a tangent M1=M2=4

now,

at gradient 4 and point (1,1)

equation of curve is ,

y-y1= m(x-x1)

or, y-1=4(x-1)

or, y-1=4x-4

or, y-4x= -3

or, 4x-y=3

5 0
3 years ago
Read 2 more answers
Cant seem to figure out the total surface area
ki77a [65]

Answer:

189

Equation for surface area is 2bs +b squared ( b is base and a is side)

Step-by-step explanation:

2bs+b squared

2 * 7 * 10=140

B squared = 7 squared which is 49

140 + 49=189.

Hope it helped.

5 0
3 years ago
2x-y=-1 , 3x-y=2 solve by substition
Mazyrski [523]

Answer:

x = 3, y = 7

or (3,7)

Step-by-step explanation:

We are given the system of equations below:

\large{ \begin{cases} 2x - y =  - 1 \\ 3x - y = 2 \end{cases}}

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.

By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

\large{ \begin{cases} y=  2x + 1\\ 3x - y = 2 \end{cases}}

Then we substitute y = 2x+1 in the second equation.

\large{3x - (2x + 1) = 2}

Use the distribution property.

\large{3x - 2x - 1 = 2}

Isolate x-term to solve the equation.

\large{x = 2 + 1} \\  \large{x = 3}

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

\large{2x - y =  - 1}  \\  \large{2(3) - y =  - 1} \\  \large{6 - y =  - 1}

Isolate and solve for y-term.

\large{6 + 1 = y} \\  \large{7 = y} \\  \large{y = 7}

Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)

Hence, the solution is (3,7)

7 0
3 years ago
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