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2 years ago

Help ill reward brainest

Mathematics

1 answer:

inna [77]2 years ago

3 0

0.876 is your answer, because it rounds to 0.88 (88 hundredths)

As you know, the hundredths place is two numbers to the right of the decimal. And 4 & below in the next position round down, while 5 & up round up.

So number / rounded:

0.088 / 0.09
0.874 / 0.87
0.876 / 0.88
0.869 / 0.87

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Tìm nghiện của đa thức <br> A.x-2<br> B.2x-7<br> C.(X-4)*(2-3X

Vitek1552 [10]

Answer:

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2 years ago

If 3.N=1,then N is the

rosijanka [135]

3 * N = 1

The multiplicative inverse is just the reciprocal of the number. The reciprocal is just " flipping " the number. So the reciprocal of 3 (or 3/1) is 1/3. And any time u multiply a number by its multiplicative inverse (reciprocal), the result is 1

3 * 1/3 = 3/3 = 1.....so N is ur multiplicative inverse

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3 years ago

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Ostrovityanka [42]

Answer: B is the answer yup B

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2 years ago

Describe some real-world situations that remind you of the coordinate plane.

Sloan [31]

Answer:

-The latitude and longitude lines on maps of the Earth

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2 years ago

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters are given as follows:

$\overline{x} = 111000, \sigma = 36730, n = 36$

Hence, the lower bound of the interval is:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002$

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

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1 year ago