The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
The answer is c, a, b, d
Step-by-step explanation:
The solution is x=16. hope it helps
<span>step 1 :</span> 3 • (x - 9) - 30 = 0
<span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
3x - 57 = 3 • (x - 19)
<span>Equation at the end of step 3 :</span> 3 • (x - 19) = 0
<span>Step 4 :</span>Equations which are never true :
<span> 4.1 </span> Solve : 3 = 0
<span>This equation has no solution.
</span>A a non-zero constant never equals zero.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : x-19 = 0<span>
</span>Add 19 to both sides of the equation :<span>
</span> x = 19
One solution was found : <span> x = 19</span>
