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iVinArrow [24]
2 years ago
13

A line of best fit can be established with which of the following? Select all that apply.

Mathematics
1 answer:
garri49 [273]2 years ago
6 0
Line of best fit also known as a linear regression or a trend line, the line of best fit is common tool for showing how two variables are related.This can be established by:
Positive correlation
all scatter plots
negative correlation
Line of best fit is used in order to demonstrate any observed trends in order to predict future outcomes regarding the data point variable in use. 
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What is the slope-intercept equation of a line with a slope of 1 and a y-intercept of 3/5?
Monica [59]

your answer should be C) y= -3/5x

because y=mx+b

the m=slope

b= y-intercept


3 0
3 years ago
Read 2 more answers
franklin deposited $75 in a no-interest bank account when he opened it. After that, he deposits $50 per month in the account. As
Furkat [3]
To solve this question the equation is
175=75+50m
Where m is the number of months
Solve the equation for m
175-75=50m
100=50m
M=100÷50
M=2 months
8 0
2 years ago
Determine the open intervals on which the graph of f(x) = x - 4cos x is concave upward or concave downward
bazaltina [42]

The graph of the function f(x) is

  • concave upward, when f''(x)>0;
  • concave downward, when f''(x)

Find f''(x):

1.

f'(x)=(x-4\cos x)'=1+4\sin x;

2.

f''(x)=4\cos x.

Now:

1. when 4\cos x>0, the graph of the function is concave upward and this is for

x\in \left(-\dfrac{\pi}{2}+2\pi k,\dfrac{\pi}{2}+2\pi k\right), \text{ where } k\in Z.

2.  when 4\cos x the graph of the function is concave downward and this is for

x\in \left(\dfrac{\pi}{2}+2\pi k,\dfrac{3\pi}{2}+2\pi k\right), \text{ where } k\in Z.

6 0
2 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
2 years ago
In Exercise, describe how the graph of g is related to the graph of f.<br> g(x)=-1+f(x)
Jet001 [13]

Answer:

The graph of g is the graph of f shifted down 1 unit.

Step-by-step explanation:

Suppose you have a function y = f(x), you can do these following operations on the function:

Shift up a units: y = f(x) + a

Shift down a units: y = f(x) - a

Shift left a units: y = f(x + a)

Shift right a units: y = f(x - a)

In this problem, we have that:

g(x) = -1 + f(x) = f(x) - 1

So the graph of g is the graph of f shifted down 1 unit.

7 0
3 years ago
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