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vodka [1.7K]
4 years ago
12

How do i verify? (1-cos^2 x)(1+tan^2 x)=tan^2 x

Mathematics
1 answer:
andre [41]4 years ago
7 0

Answer:

(1-cos^2 x)(1+tan^2 x)=tan^2 x is an identity

Step-by-step explanation:

use pictomath

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I will give brainly
sammy [17]
Hello, I just did this lesson and I want to say the answer is 17%. I’m not 100% sure on that answer and I wanted to give you a heads up on that. I hope this is right!
6 0
3 years ago
Help!!
hjlf

Answer: 1/2

Explanation: There are 5 vowels and 5 consonants in the word believable. So to find the consonant, you have to do a fraction with consonant as numerator and the total number of letters as the denominator. Since there are 5 consonants and 10 letters in total, the simplest form will be 1/2.

8 0
3 years ago
someone please help, write in point-slope form an equation of the line that passes through the point (8, 9) with slope 7.
Bess [88]

Answer:

y=7x-47

Step-by-step explanation:

(8, 9) = (x_1,y_1) \\ m = 7 \\ y  - y_1 = m(x - x _1) \\ y - 9 = 7(x - 8)

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7 0
3 years ago
Find the unknown length x in each right triangle ,to the nearest tenth
vladimir2022 [97]
That is a 3, 4, 5 right triangle.

Since 5 × 3 = 15 everything is multiplied by 3

3 × 3 = 9 ( the smaller leg )

4 × 3 = 12 ( the longer leg )

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Answer : 9

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I hope that helps you out!!

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3 0
3 years ago
"In order to estimate the average electric usage per month, a sample of 33 houses were selected and the electric usage determine
JulijaS [17]

Answer:

2,157.89 KWH is the upper bound of the interval estimate for the population mean.

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 2,000 KWH

Sample size, n = 33

Alpha, α = 0.01

Population standard deviation, σ = 106 KWH

99% Confidence interval:

\mu \pm z_{critical}\dfrac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.01} = 2.58

2000 \pm 2.58(\dfrac{106}{\sqrt{3}} )\\\\ = 2000 \pm 157.89 \\\\= (1842.11,2157.89)

2,157.89 KWH is the upper bound of the interval estimate for the population mean

4 0
3 years ago
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