Please answer this question correctly please

Helpppppppppppppppppppppppppppppppppppppp

DedPeter [7]

Answer:

For every 15 students scoring in the 60's there were 9 students scoring in the 70's.

Step-by-step explanation:

Your first step would be to rewrite the numbers into an easier to understand form like fractions, 45/3 and 27/3. Then you divide both numbers by 3, so you get comparable numbers. 45/3= 15, 27/3=9.

5 0

3 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0$

So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.

5 0

3 years ago

The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of

ivanzaharov [21]

<h2>Answer:</h2>

$R_2$ is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors $R_1$ and $R_2$ connected together in parallel, the total resistance $R_T$ is given by;

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ ---------(i)

<em>Make </em> $R_2$ <em> subject of the formula;</em>

=> $\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}$

=> $\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}$

=> ${R_2} = \frac{R_TR_1}{R_1 - R_T}$ ---------------(ii)

From the question,

$R_1$ = 6Ω

$R_T$ = 2Ω

Substitute these values into equation (ii) as follows;

=> ${R_2} = \frac{2*6}{6 - 2}$

${R_2} = \frac{12}{4}$

$R_2$ = 3Ω

Therefore, the value of $R_2$ = 3 ohms or $R_2$ = 3Ω

3 0

3 years ago

A cylinder-shaped drainage pipe 66 in. long measures 25.12 in. around.

Darina [25.2K]

V=hpir^2

tricky, they didn't give us radius
they just gave circiufmerece

c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r

subsitutet

v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches

4 0

3 years ago

there are 20 guests at a party. the host has 8 gallons of punch. he estimates that each guest will drink 2 cups of punch. if he

Rina8888 [55]

Answer: He will have 88 cups of punch left over

Step-by-step explanation:

6 0

3 years ago

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