Answer:
y = x-4
Step-by-step explanation:
y = -x-5
Slope of line is -1.
Slope of perpendicular to line is 1.
Point-slope equation for line of slope 1 that passes through (6,2):
y-2 = 1(x-6)
Rearrange equation to slope-intercept form:
y = 1(x-6) + 2
y = x-4
You divide -15 on both sides to keep the x alone
-240/ -15=16
A negative divided by a negative is a positive so x=16
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
45. divide the first set of x and y by 2 then multiply by 9 to get 45 for y and 18 for x
Using cos addition formula:
use x for theta
cos(x+π/6)=cosx*cos(π/6)-sinx*sin(π/6)
sinx=1/4
cosx=√15/4
cos(π/6)=√3/2
sin(π/6)=1/2
cos(x+π/6)=(√15/4*√3/2)-(1/4*1/2)
cos(x+π/6)=(√45/8)-(1/8 )
cos(x+π/6)=(√45-1)/8)
