35<em>x</em>² = 7<em>x</em> • 5<em>x</em>, and
5<em>x</em> (7<em>x</em> + 3) = 35<em>x</em>² + 15<em>x</em>
Subtract this from the dividend to get an initial remainder of
(35<em>x</em>² - 48<em>x</em> - 27) - (35<em>x</em>² + 15<em>x</em>) = -63<em>x</em> - 27
-63<em>x</em> = 7<em>x</em> • (-9), and
-9 (7<em>x</em> + 3) = -63<em>x</em> - 27
Subtract this from the previous remainder to get a new one of
(-63<em>x</em> - 27) - (-63<em>x</em> - 27) = 0
and we're done.
Now just gather the terms in bold (and the remainder, but since it's 0 we leave it out). So we have
(35<em>x</em>² - 48<em>x</em> - 27) / (7<em>x</em> + 3) = 5<em>x</em> - (63<em>x</em> + 27) / (7<em>x</em> + 3)
(35<em>x</em>² - 48<em>x</em> - 27) / (7<em>x</em> + 3) = 5<em>x</em> - 9
Answer:
6 Gallons per min
Step-by-step explanation
Unit rate is a fraction that has a one in the denominator
so you have 42/7 = n/1 so to make 7 a 1 , we divide by 7 . We do the same thing on top 42 divided by 7 is 6.
Answer:
7/40
Step-by-step explanation:
probability of taking 7 vehicles from 10 vehicles = 10C₇
number of ways taking 2 SUVs and 5 trucks = 3C₂* 7C₅ = 63
number of ways taking 3 SUVs and 4 trucks =3C₁*7C₄ = 35
number of ways taking 2 SUVs and 5 trucks or 3 SUVs and 4 trucks = 63 + 35 = 98
The probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks is = 98/120 = 49/60
number of ways taking 7 randomly chosen vehicles, exactly 1 is an SUV = 3C₁*7C₆ = 21
The probability that of any 7 randomly chosen vehicles, exactly 1 is an SUV is 21/120 = 7/40
C = 2 pi r
C = 2 x 3.14 x 12.5
C = 78.5 cm
answer is C. 78.5 cm
Since the object is larger, the dilation can not be negative and less than 1. Therefore, your answer is 1.25 (d). Also, 4 * 1.25 is 5.