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Elenna [48]
3 years ago
5

Suppose matrix D is the inverse of matrix C. Which of the following is equal to D?

Mathematics
2 answers:
denpristay [2]3 years ago
7 0

CDD cause CD=I and then ID=D

Hope I helped.

mr Goodwill [35]3 years ago
6 0

Answer: (A) CDD

if D=C^-1

then

C D D = (C C^-1) D = I D = D

(where I is the identity matrix)

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Part (1) : The solution is 729

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

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Part (1): The expression is 3^{2} \cdot3^{4}

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Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

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$\frac{1}{16 x^{8}}$

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Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

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Adding the powers, we get,

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$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

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