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3 years ago

Is 22/35 inits simplest form??

Mathematics

2 answers:

Dvinal [7]3 years ago

4 0

Yes it is at its simplest form

wolverine [178]3 years ago

3 0

Yes it’s the simplest form

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Easy brainliest for correct answer 100%

Alik [6]

Answer:

It would be the last option.

8 0

3 years ago

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Here is a table of values for y = f(x).

DanielleElmas [232]

the complete question in the attached figure

statements

case A) f(15)=8-----> is correct

for x=15

f(x)=8

case B) the domain of f(x) is the set {5,6,7,8,10,11,12,13}--> is not correct

because the domain of f(x) is the set {0,5,10,15,20,25,30,35,40}

case C) f(5)=6-----> is correct

for x=5

f(x)=6

case D) the range for f(x) is all real numbers----> is not correct

because

the range of f(x) is the set {5,6,7,8,9,10,11,12,13}

the answer is

A and C

7 0

3 years ago

Out of $20$ creepy-crawly creatures in a room, $80\%$ are flies and $20\%$ are spiders. If $S\%$ of the total legs belong to spi

Alex_Xolod [135]

Answer: 25

Step-by-step explanation:

Since, Total creepy-crawly creatures = 20

Out of which 80% are flies and 20% are spiders,

Thus, the total flies = 80% of 20 = 16

And, The total spiders = 20% of 20 = 4

Also, we know that the number of legs of a spider = 8,

⇒ Total legs belong to spiders out of 20 creepy-crawly creatures = 4×8 = 32

Again, the number of legs of a fly = 6

Thus, the total legs belong to flies out of 20 creepy-crawly creatures = 6×16 = 96

Hence, Total legs = 32 + 96 = 128

$\text{ The percentage of legs that belongs to spider} = \frac{ \text{ Number of legs of 8 spiders}}{\text{ Total legs}}\times 100$

$= \frac{32}{128} \times 100$

$= \frac{3200}{28}$

$= 25\%$

7 0

3 years ago

WILL GIVE BRAINLIEST

vladimir2022 [97]

Answer:

2 to 3, 4 to 6, 8 to twelve

Step-by-step explanation:

the boys are first, girls second

5 0

3 years ago

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Solve the differential equation y prime equals the product of 2 times x and the square root of the quantity 1 minus y squared .

MatroZZZ [7]

Answer:

1. y = sin(x²+C)

2. see below

Step-by-step explanation:

1. $\frac{dy}{dx} = 2x\sqrt{1-y^2}$

separation of variables

$\frac{dy}{\sqrt{1-y^2} } = 2xdx$

integration both sides $\int\frac{dy}{\sqrt{1-y^2} } = \int2xdx$

you should get :

$sin^{-1} (y) = x^2+C$ remember constant of integration!!

2. y = sin(x²+C)

3 = sin(0+C)

y(0) = 3 does not have a solution because our sin graph is not shifted vertically or multiplied by a factor whose absolute value is greater than 1, so our range is [-1,1] and 3 is not part of this range

4 0

4 years ago