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pshichka [43]
3 years ago
8

Choose the two numbers from the box to complete

Mathematics
1 answer:
o-na [289]3 years ago
4 0

Answer:

455 & 571

Step-by-step explanation:

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Select all statements that show correct reasoning for finding 15 = 3
mario62 [17]

Answer:

. Multiply 15 by 1, then divide by 5

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A line is parallel to y = 3x + 8 and
Ad libitum [116K]

Answer:

y= 3x+16

Step-by-step explanation:

y = 3x + 8 ║ y= mx +b

Since lines are parallel, m=3

y= 3x+b

(-3, 7) intersect

  • 7= 3*(-3) + b
  • b= 7+9
  • b= 16

y= 3x+16

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3 years ago
If the radius of the wheel below is 4.2 inches. What is the area of the wheel? Round to the nearest tenth place value.
zepelin [54]

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A = 55.4 in^2

Step-by-step explanation:

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A 12-foot ladder is leaning against a building with the base of the ladder 5 feet from the building. How can you find how high o
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Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
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