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3 years ago

Can you help me find this ans

Mathematics

1 answer:

Alisiya [41]3 years ago

6 0

Answer:

12 CD

11 cu

17 Br

15 p

b.group 18

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The average price of a movie ticket in the United States from 1980 to 2000 can be modeled by the expression, 2.75+0.10x, where x

MissTica

Answer:

Step-by-step explanation:

step one:

Let the cost be y

to solve for the cost of a movie ticket, we need to solve the expression

y=2.75+0.10x

step two:

given that x is the number of years between 1980-2000

the number of years is 20years

put x= 20 in the expression for the cost we have

y=2.75+0.10(20)

y=2.7+2

y=$4.7

5 0

2 years ago

Determine whether the statement below is always, sometimes, or never true. two lines with positive slopes are parallel.

elena-s [515]

Always because according to my calculations

8 0

2 years ago

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the circle below has center T. suppose that m UV = 138 degrees and that UW is tangent to the circle at U. find the following

alisha [4.7K]

Angle UTV is basically given: it's 138°.

Moreover, since UTV is isosceles, the other two angles have the same measure x. We thus have

$138+x+x=180 \iff 2x=42 \iff x=21$

So, TUV is 21°, and VUW is complementary, so it must be 69° so that they sum up to 90°

3 0

3 years ago

11w +99 < 33 algebra answer

Otrada [13]

Answer:

w<-6

Step-by-step explanation:

11w+99<33

-99

11w<-66/11

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2 years ago

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A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$

To maximize the area, we derive and equal to zero:

$\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36$

Then, b is:

$b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68$

3 0

3 years ago

Can you help me find this ans​

Can you help me find this ans