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Lesechka [4]
4 years ago
6

Can you help me find this ans​

Mathematics
1 answer:
Alisiya [41]4 years ago
6 0

Answer:

12 CD

11 cu

17 Br

15 p

b.group 18

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Prove that the function
Stella [2.4K]

Answer:

See proof below

Step-by-step explanation:

<u>Important points</u>

  • understanding what it means to be "onto"
  • the nature of a quadratic function
  • finding a value that isn't in the range

<u>Onto</u>

For a function with a given co-domain to be "onto," every element of the co-domain must be an element of the range.

However, the co-domain here is suggested to be \mathbb R, whereas the range of f is not \mathbb R (proof below).

<u>Proof (contradiction)</u>

Suppose that f is onto \mathbb R.

Consider the output 7 (a specific element of \mathbb R).

Since f is onto \mathbb R, there must exist some input from the domain \mathbb R, "p", such that f(p) = 7.

Substitute and solve to find values for "p".

f(x)=-3x^2+4\\f(p)=-3(p)^2+4\\7=-3p^2+4\\3=-3p^2\\-1=p^2

Next, apply the square root property:

\pm \sqrt{-1} =\sqrt{p^2}

By definition, \sqrt{-1} =i, so

i=p \text{ or } -i =p

By the Fundamental Theorem of Algebra, any polynomial of degree n with complex coefficients, has exactly n complex roots.  Since the degree of f is 2, there are exactly 2 roots, and we've found them both, so we've found all of them.

However, neither i  nor -i are in \mathbb R, so there are zero values of p in \mathbb R for which f(p)= 7, which is a contradiction.

Therefore, the contradiction supposition must be false, proving that f is not onto \mathbb R

3 0
2 years ago
7
LUCKY_DIMON [66]

The answer is B. 15 cm

5 0
3 years ago
When I get multiplied by any number, the sum of the figures in the product is always me. What am I?
vladimir1956 [14]

Answer: 9

Step-by-step explanation:

When you multiply 9*9, you get 81 whose sum is 9 (8+1)

Likewise, 9*8=72( 7+2=9)

8 0
3 years ago
Read 2 more answers
Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)
muminat

Answer:

The equation of line parallel to given line and passing through points        ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = \frac{-5}{2} x + \frac{12}{2}

Or, y = \frac{-5}{2} x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = \frac{-5}{2}

Again,

The other line if passing through the points (- 2 , 3 ) And  is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So,  M = m = \frac{-5}{2}

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = \frac{-5}{2} × ( - 2 ) + c

or, 3 =  \frac{10}{2} + c

Or, 3 = 5 + c

∴  c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope  \frac{-5}{2}  and passing through points ( -2 , 3)

y =  \frac{-5}{2} x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And  is perpendicular  to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So,  M' × m = - 1

Or, M' ×  \frac{-5}{2} = - 1

Or, M' = \frac{-1}{\frac{-5}{2}}

Or, M' =  \frac{2}{5}

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = \frac{2}{5} × ( - 2 ) + c'

or, 3 =  \frac{- 4}{5} + c'

Or, 3 × 5 = - 4 + 5× c'

∴  5 c' = 15 + 4

or, 5 c' = 19

Or, c' =  \frac{19}{5}

So, The equation of line with slope  \frac{2}{5}  and passing through points ( -2 , 3)

y =  \frac{2}{5} x +  \frac{19}{5}

y =  \frac{2 x + 19}{5}

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And  The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0
3 years ago
I have 25% off coupon that I would like to apply to this purchase.” Since the sticker price is $93.78,the actual cost to you wil
levacccp [35]

Answer:

$70.33

Step-by-step explanation:

sticker price = $93.78

discount coupon in percentage = 25%

Thus, discount will be 25% of sticker price

discount amount = 25% of  $93.78 = 25/100 *  $93.78 = $23.45

Thus, amount paid = sticker price - discount amount  =  $93.78-$23.45

amount paid = $70.33

actual cost to you will be what after discount applied is $70.33

4 0
4 years ago
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