Its the third one..........
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
The maximum variance is 250.
Step-by-step explanation:
Consider the provided function.
Differentiate the above function as shown:
The double derivative of the provided function is:
To find maximum variance set first derivative equal to 0.
The double derivative of the function at is less than 0.
Therefore, is a point of maximum.
Thus the maximum variance is:
Hence, the maximum variance is 250.
Answer:
4
−
3
Step-by-step explanation:
