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saul85 [17]
4 years ago
15

What is 3/5 + 1/2 in simplest form

Mathematics
2 answers:
timofeeve [1]4 years ago
6 0
3/5 + 1/2
= 6/10 + 5/10
= 11/10
= 1.1 so the answer is 1.1
omeli [17]4 years ago
6 0
You add 3/5+ 1/2 which = 11/10

divide 11 in to 10 which gives you 1 and 1/10

answer 1 and 1/10 or 1.1



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Please help me with all these questions . I really appreciate it but if you don't how to do it please comment don't answer the q
frozen [14]
For number 1, add the sides of the triangle. They are all given. The answer is 19.

For number 2, you use the formula for circumference, 2 times pi times radius. The answer is 43.96.

For number 3, I assume that 5 is half of one side. You would double 5 to get ten and multiply it by four, since there are four sides in a square. The answer is 40.

For number 4, you would multiply 5 times pi, but don't solve it. ( since the directions are to leave the answer in terms of pi) The answer is 5 pi.

For number 5, add all the sides together like number 1. The answer is 18.
8 0
3 years ago
Read 2 more answers
Please help answer this​
Naddik [55]
N/2-9=37 and it says I need 20 characters so don’t mind me typing lol
5 0
3 years ago
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Image P is shown in the coordinate grid Image P is translated 2.5 units to the right and 3.5 units up to create image P'.
Ksju [112]

Answer:

Here we do not have the image P, but let's solve this in a general way.

Suppose that we have a point A (x,y)

If we translate the point A n units horizontally (where n can be positive, translation to the right, or negative translation to the left.)

The new point will be (x + n, y)

if we translate the point m units vertically (if m is positive the translation is upwards, if m is negative the translation is downwards), the new point will be (x + n, y + m)

Then if our figure was p (x, y)

The new figure is p(x + 2.5, y + 3.5)

So for every point in the figure, we need to add 2.5 to the x component, and 3.5 to the y-component.

6 0
3 years ago
Find the distance between each pair of points:
rusak2 [61]

Answer:

The distance between points P(x

1

,y

1

,z

1

) and Q(x

2

,y

2

,z

2

) is given by

PQ=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

+(z

2

−z

1

)

2

(i) Distance between points (2,3,5) and (4,3,1)

=

(4−2)

2

+(3−3)

2

+(1−5)

2

=

(2)

2

+(0)

2

+(−4)

2

=

4+16

=

20

= 2

5

(ii) Distance between points (−3,7,2) and (2,4,−1)

=

(2+3)

2

+(4−7)

2

+(−1−2)

2

=

(5)

2

+(−3)

2

+(−3)

2

=

25+9+9

=

43

(iii) Distance between points (−1,3,−4) and (1,−3,4)

=

(1+1)

2

+(−3−3)

2

+(4+4)

2

=

(2)

2

+(−6)

2

+(8)

2

=

4+36+64

=

104

=2

26

(iv) Distance between points (2,−1,3) and (−2,1,3)

=

(−2−2)

2

+(1+1)

2

+(3−3)

2

=

(−4)

2

+(2)

2

+(0)

2

=

16+4

=

20

= 2

5

6 0
2 years ago
Write the value of the underlined digit 7,270
RSB [31]

I am sorry but I do not see the underlined digit, but I will put it this way. 7 in the thousands place is worth 7000, 2 in the hundreds place is worth 200, 7 in the tens place is worth 70, and 0 in the ones place is worth 0.

Hope this helped!

Nate

3 0
4 years ago
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