A. $35.00
1 answer:
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The equation in slope-intercept form for this function is y = 8 x
The slope represents the unit cost
A party for 40 people would cost $320
Step-by-step explanation:
The linear equation in the form of slope-intercept is:
y = mx + b, where m is the slope of the line and b is the y-intercept
, where
and
are two points on the line
- To find b substitute x and y of the equation by the coordinates of any point on the line
A caterer charges $120 to cater a party for 15 people and $200 for
25 people.
Assume that the cost, y, is a linear function of the number of people x
We need to write an equation in slope-intercept form for this function
We need to explain that the slope represent what
We need to find how much a party for 40 people would cost
∵ The slope-intercept form of the equation is y = mx + c
∵ y is the cost and x is the number of people
∴ x = 15 and y = 120 is a point on the line
∴ x = 25 and y = 200 is another point on the line
- Now we can use them to find the slope of the line
∵
∴ m = 8
∴ y = 8 x + b
- To find b substitute x by 15 and y by 120 in the equation
∴ 120 = 8(15) + b
∴ 120 = 120 + b
- Subtract 120 from both sides
∴ b = 0
∴ y = 8 x
The equation in slope-intercept form for this function is y = 8 x
∵ The slope = change of y ÷ change of x
∴ The slope = cost ÷ number of people
∴ The slope represents the cost per person
The slope represents the unit cost
∵ There are 40 people
∴ x = 40
∵ The equation of the cost is y = 8 x
∴ y = 8 × 40
∴ y = 320
∴ The cost is $320
A party for 40 people would cost $320
Learn more:
You can learn more about the linear function in brainly.com/question/4152194
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Answer:
Step by step explanation:
Please find the attachment.
We have been given that the length of a diagonal of a quadrilateral shaped field Is 48 m. The length of perpendicular dropped on it from the remaining apposite vertices are 16 m and 26 m.
We can see from our attachment that diagonal AC divides our quadrilateral field into two triangular fields and AC will be the base of both triangles.
To find the area of our given quadrilateral we will find the areas of both triangles and add the areas.
Let us find area of triangle ABC with base 48 m and height 26 m.
Therefore, the area of triangle ABC will be 624 square meters.
Now let us find area of triangle ADC with base 48 m and height 16 m.
Therefore, the area of triangle ADC will be 384 square meters.
Now let us add areas of triangles ABC and ADC to get the area of our quadrilateral ABCD.
Therefore, the area of quadrilateral shaped field will be 1008 square meters.
