Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?
Answer:
v = 80 cubic unit
Step-by-step explanation:
volume = length × height × width
v = 5unit × 2unit × 8unit
v = 80 cubic unit
The probability of you rolling a 5 would be 1/6 since the cube has 6 sides and only one of the sides has a 5.
The probability that you either roll a 5 or do not roll a 5 would be 6/6 because 1/6, the probability you WILL roll a 5, and 5/6, the probability you WON'T roll a 5 added together is 6/6.
The probability that you don't roll a 5 is 5/6 because there are 5 sides of the dice that are not 5.
Hope that helped!
It is generally useful to use the formula. The procedure is to substitute the given values for the variables in the formula, then do the arithmetic.
... A = (1/2)r²·θ . . . . r is the radius, θ is the central angle in radians
Put the numbers in ...
... A = (1/2)(4 in)²·(π/3)
... A = 8π/3 in² ≈ 8.37758 in²
