The population of a city is growing at an average rate of 3% per year in 1990 the population was 45 000.
1 answer:
This is an exponential growth/decay problem...
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case:
F=I(1.03)^t and they just want to know when F=2I so
2=1.03^t take natural log of both sides...
ln2=t*ln1.03
t=ln2/(ln1.03)
t≈23.45
So it will take approximately 23.45 years for the population to double..
1990+23.45=2013.45
So during the year of 2013 the population will have double from its 1990 level.
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