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matrenka [14]
3 years ago
5

The population of a city is growing at an average rate of 3% per year in 1990 the population was 45 000.

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0
This is an exponential growth/decay problem...

F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case:

F=I(1.03)^t  and they just want to know when F=2I so

2=1.03^t  take natural log of both sides...

ln2=t*ln1.03

t=ln2/(ln1.03)

t≈23.45

So it will take approximately 23.45 years for the population to double..

1990+23.45=2013.45

So during the year of 2013 the population will have double from its 1990 level.
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Which is the total surface area of this cone?
disa [49]

Answer:

  A.  219.80 square centimeters

Step-by-step explanation:

The total surface area is given by ...

  A = πr(r+s)

where r is the radius and s is the slant height. Filling in the given numbers, you get ...

  A = 3.14·(5 cm)·(5 cm +9 cm) = 219.80 cm²

3 0
3 years ago
What is mZDAR in circle A?
Andreas93 [3]

Answer:

68°

Step-by-step explanation:

Since, angle subtended on the circumference of the circle is half angle subtended on the center of the circle.

\therefore m\angle DBR = \frac{1}{2} \times m\angle DAR\\\\\therefore 34\degree = \frac{1}{2} \times m\angle DAR\\\\\therefore 34\degree \times 2= m\angle DAR\\\\\therefore 68\degree = m\angle DAR\\\\\therefore m\angle DAR=68\degree

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3 years ago
Write each multiplication equation in the correct box.
juin [17]

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Figure it on your own

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Because i said so

5 0
3 years ago
Supposed soda is on sale for $0.50 can and you have a coupon for $0.80 off your total purchase write a function rule for the cos
shepuryov [24]

As per the problem

Soda is on sale for $0.50.

and you have a coupon for $0.80 off your total purchase.

we are supposed to write a function rule for the cost of an can of soda.

If you buy x cans of soda then the cost function can be written as

C(x)=0.5x-0.80\\ \\ \text{we can replace x by the number of cans, here we have x=1 }\\ \\ C(1)=0.50*1-0.80

6 0
3 years ago
Read 2 more answers
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58 dash m​-by-5
svetoff [14.1K]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

5 0
3 years ago
Read 2 more answers
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