Formula: sqr((x2-x1)^2 + (y2-y1)^2)
sqr((-4-2)^2 + (-7+2)^2)
sqr(-6)^2 + (-5)^2)
sqr(36)+(25)) = sqr(61)
The answer is A. sqr(61)
Answer:
1/4
Step-by-step explanation:
sorry for the messy work
You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.
If the
coefficient is 1, i.e. the equation is written like
, then you can say the following about the coefficients b and c:
is the opposite of the sum of the roots
is the multiplication of the roots.
So, for example, if we want an equation whose roots are 4 and -2, we have:
So, the equation is 
If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:
And so the equation is

In order to have integer coefficients, you can multiply both sides of the equation by 8:

Answer: Min = (0.5, −6.25)
Step-by-step explanation: Standard form:
x2 − x − 6 = 0
Factorization:
(x + 2)(x − 3) = 0
Solutions based on factorization:
x + 2 = 0 ⇒ x1 = −2
x − 3 = 0 ⇒ x2 = 3