Answer:
31-3n
Step-by-step explanation:
d=-3
a1=28
an= 28+(n-1)(-3)=28-3n+3
an=31-3n
Answer:
Given that a polynomial has a constant term and at least one other term what is the minimum number of possible zero values based on the rational zero test? a-0 b-2 c-3 d-4
Answer:
A(h) = h²/2 - 6*h + 10
Step-by-step explanation:
The garden is rectangular, and area of a rectangle is:
A(r) = L*w
Where L is the length and w is the width of the rectangle
Now if we call "h" the length of the house, we have the following expressions
L = h - 2 and
w = h/2 - 5
The expression for the area f the ectangle as a function of the length of the house is:
A(h) = ( h - 2 )* ( h/2 -5 )
A(h) = h²/2 - 5*h - h + 10
A(h) = h²/2 - 6*h + 10
The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11
<h3>How to solve the function values?</h3>
As a general rule, we have:
f⁻¹(f(x)) = x
Substitute 58 for x
So, we have:
f⁻¹(f(58)) = 58
Hence, the value of f⁻¹(f(58)) is 58
Also, we have:
f(f(5))
From the table, we have:
f(5) = 9
So, we have:
f(f(5)) = f(9)
From the table, we have:
f(9) = 11
So, we have:
f(f(5)) = 11
Hence, the value of the function f(f(5)) is 11
Read more about invertible function at:
brainly.com/question/14391067
#SPJ1
the one that starts with (-2,-2)
