Answer:
Please help with these few questions
6. Use the picture to find the following angle measures.
9. Write a two -column proof for the following :
Given: angle1 and angle2 form a linear pair and m angle1= 2(m angle2)
Prove : m angle2 =60
10. Write a two-column proof for the following:
Given : AB = CD , AB = 4x + 1, and CD = 6x - 13
Prove: x = 7
Step-by-step explanation:
Please help with these few questions
6. Use the picture to find the following angle measures.
9. Write a two -column proof for the following :
Given: angle1 and angle2 form a linear pair and m angle1= 2(m angle2)
Prove : m angle2 =60
10. Write a two-column proof for the following:
Given : AB = CD , AB = 4x + 1, and CD = 6x - 13
Prove: x = 7
Answer:
The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).
Answer:
The unknown angle is 80
Step-by-step explanation:
The sum of the angles of a triangle add to 180 degrees
Let the unknown angle be x
20+80+x = 180
Add like terms
100+x = 180
Subtract 100 from each side
100-100+x=180-100
x = 80
Answer:
Try to ;look it up! ON google or CHROME.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the side of the square base be x
h be the height of the box
Volume V = x²h
13500 = x²h
h = 13500/x² ..... 1
Surface area = x² + 2xh + 2xh
Surface area S = x² + 4xh ...... 2
Substitute 1 into 2;
From 2; S = x² + 4xh
S = x² + 4x(13500/x²)
S = x² + 54000/x
To minimize the amount of material used; dS/dx = 0
dS/dx = 2x - 54000/x²
0 = 2x - 54000/x²
0 = 2x³ - 54000
2x³ = 54000
x³ = 27000
x = ∛27000
x = 30cm
Since V = x²h
13500 = 30²h
h = 13500/900
h = 15cm
Hence the dimensions of the box that minimize the amount of material used is 30cm by 30cm by 15cm
