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sammy [17]
3 years ago
6

?????????????!???????!???!?????

Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

249.6

Step-by-step explanation

There are 4 identical equilateral triangle,

we can find the area of one and multiply by 4

area of triangle = \frac{1}{2} *base*hight=\frac{1}{2}*12*10.4=62.4

now 62.4*4 = 249.6

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HELP ME WOTH THIS QUESTIONNN!!
bekas [8.4K]

Answer:

C

Step-by-step explanation:

For lines l and m and the transversal line that creates angles 6 and 18, angles 6 and 18 are corresponding angles of lines l and m. If they are congruent, lines l and m are parallel.

Answer: Choice C

8 0
2 years ago
I need help with my geometry work please.
cricket20 [7]

Answer:

AA

Step-by-step explanation:

The steps are F and H are matched with line marking it congruent and G is vertical and the last is congruent.

5 0
3 years ago
Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal
cricket20 [7]

Answer:

The arc length of the semicircle is 5 \pi\ units or 15.7\ units

Step-by-step explanation:

The complete question in the attached figure

we know that

The circumference of a semicircle is given by the formula

C=\frac{1}{2}\pi D

where

D is the diameter of the semicircle

we have

D=10\ units

substitute

C=\frac{1}{2}\pi (10)

C=5 \pi\ units ----> exact value

Assume

\pi =3.14

C=5(3.14)=15.7\ units ----> approximate value

therefore

The arc length of the semicircle is 5 \pi\ units or 15.7\ units

6 0
3 years ago
Convert,the complex number into polar form: 4+4i
kow [346]
Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
 r = 4√(2)
 r = 4(1.414)
 r = 5.656

cos\theta = \frac{a}{r}
cos\theta = \frac{4}{4\sqrt{2}}
cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}
cos\theta = \frac{4\sqrt{2}}{4(2)}
cos\theta = \frac{4\sqrt{2}}{8}
cos\theta = \frac{\sqrt{2}}{2}
2(cos\theta) = 2(\frac{\sqrt{2}}{2})
2cos\theta = \sqrt{2}
2cos\theta = 1.414

sin\theta = \frac{b}{r}
sin\theta = \frac{4}{4\sqrt{2}}
sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}
sin\theta = \frac{4\sqrt{2}}{4(2)}
sin\theta = \frac{4\sqrt{2}}{8}
sin\theta = \frac{\sqrt{2}}{2}
2(sin\theta) = 2(\frac{\sqrt{2}}{2})
2sin\theta = \sqrt{2}
2sin\theta = 1.414

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

\theta = tan^{-1}\frac{b}{a}
\theta = tan^{-1}\frac{4}{4}
\theta = tan^{-1}(1)
\theta = 45

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).
5 0
3 years ago
What does it take to become a boxer?
Murljashka [212]

Answer:

you have to have a fighting spirit

Step-by-step explanation:

6 0
3 years ago
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