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Anvisha [2.4K]
3 years ago
6

How are polynomials like and unlike monomials? Provide an example of a monomial and an example of a polynomial. How does the fol

lowing example, (5+ (-7x2) + x), fit the definition of a polynomial?
What might a binomial and a trinomial be? Give an example of a polynomial of degree 3. Of degree 6.
Mathematics
1 answer:
Ainat [17]3 years ago
8 0
A polynomial is the sum of at least one term. For example, x^3+1 is a polynomial. A monomial is a polynomial with only one term, such as 2x^2. A binomial is a polynomial with two terms, and a trinomial is one with three terms. The example you gave is a trinomial (which is also a polynomial). Degree of a polynomial is the largest sum of variable powers in any term of the polynomial. So, for example, x^2 y has degree 3, and x^3+x^2 also has degree 3. A sixth degree polynomial would be x^6-2x+1, for example.
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In how many ways can 7 charms be placed on a bracelet with no clasp?
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I believe it is 1 wayyyyy
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3 years ago
Tom makes a 8% commission on the sale of all the cars that he sells. He sells $140,000 worth of cars this month. What is the com
maks197457 [2]

Answer:

$11,200

Step-by-step explanation:

Just multiply the percent times the total

8% * 140000 = .08 * 140000 = 11200

8 0
2 years ago
How can i solve by completing the square 4r^2-28r=-49
Natalija [7]
To complete the square, the second degree term must have a coefficient of 1.
Since the second degree term here has a coefficient of 4, we start by dividing each term on both sides by 4.

4r^2 - 28r = -49

\dfrac{4r^2}{4} - \dfrac{28}{4}r = -\dfrac{49}{4}

r^2 - 7r = -\dfrac{49}{4}

Now we can complete the square.
First, we need to find what number completes the square.
We take the coefficient of the first degree term, -7 in this case.
Divide it by 2 and square it. -7 divided by 2 is the fraction -7/2.
Now we square -7/2 to get 49/4.
We add 49/4 to both sides.

r^2 - 7r + \dfrac{49}{4} = -\dfrac{49}{4} + \dfrac{49}{4}

(r - \dfrac{7}{2})^2 = 0

r - \dfrac{7}{2} = 0

r = \dfrac{7}{2}
3 0
3 years ago
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 185 m above the groun
agasfer [191]

Answer:

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

Step-by-step explanation:

For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.

To find the probability of damage on a parachute, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability of a parachute having damage.

The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that \mu = 185, \sigma = 32

Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of  Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 185}{32}

Z = -2.66

Z = -2.66 has a p-value of 0.0039.

What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?

0.0039 probability of a parachute having damage, which means that p = 0.0039

5 parachutes, which means that n = 5

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

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