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Rashid [163]
3 years ago
7

Nathan has a rectangular plot of grass in his backyard that has dimensions of meters in width and meters in length. What is the

total area of the plot of grass? Recall that the area of a rectangle is the width multiplied by the length.
Mathematics
1 answer:
zalisa [80]3 years ago
5 0

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, a rectangle.

We know that the area of a rectangular shape is

Area =length x width

Since we don't have any specific data regarding Nathan's plot of land

Let's assume some figure for better understanding

Say the length is 18m

And the width is 12m

Area = 18*12

Area= 216m²

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OOOO
lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

x^4+95x^2 -500=0

Substituting x^2=a, given bi-quadratic equation reduces in the form of following quadratic equation:

a^2 +95a -500=0\\

Let us factorize the above quadratic equation:

a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\

Since square root of a negative number cannot be found, so:

x \neq \pm \sqrt{-100}\\

CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\

3 0
3 years ago
Let n be equal to 156% of 70. Which of the following proportions is true?
aniked [119]
Well all u have to do is 156%*70= 109.2 so N= 109.2
6 0
3 years ago
What is the y- intercept of the line shown?
timofeeve [1]
Y-intercept when x = 0
so 
y = 4
8 0
3 years ago
Which point could be on the line that is perpendicular
slamgirl [31]

Answer:

b (2,2)

Step-by-step explanation:

4 0
3 years ago
Consider the given matrix. 1 −1 0 5 1 4 0 1 1 Find the eigenvalues. (Enter your answers as a comma-separated list.) λ = Find the
fomenos

Answer:

Step-by-step explanation:

We have to diagonalize the matrix

\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]

we have to solve the expression

|A-\lambda I|=0

Thus, by applying the determinant we obtain the polynomial

(1-\lambda )^3+5-4=0\\(1-\lambda )^3+1=0\\

-\lambda^3+3\lambda^2-4\lambda+2

\lambda_1=1\\\lambda_2=1-i\\\lambda_3=1+i\\

and the eigenvector will be

v_1=(-4,0,5)\\v_2=(-1,-i,-1)\\v_3=(-1,i,1)

HOPE THIS HELPS!!

3 0
3 years ago
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