Answer:
The first graph best represent the given scenario.
Step-by-step explanation:
Given that Kent walked to the bus stop, then sat and waited until the bus arrived. He rode the bus for 25 minutes, then walked the last 3 blocks to work. we have to find which graph best represent the scenario.
In the first graph, it is given The line increases for 10 minutes means the distance as well as time increases i.e Kent walked for 10 minutes then, stays horizontal for 15 minutes means no distance covered i.e stop or wait for 15 minutes. After that graph increases rapidly for another 25 minutes, that means rode the bus for 25 minutes then increases slowly for 5 minutes indicate walked to work.
The above graph best represent the scenario.
All three option is analysed by graphing which doesn't show the above given scenario.
To do this you times 3 by 4 and add it on to the numerator of the fraction, to turn it into a top heavy fraction:
3*4 = 12
1+12/3 = 13/3
Then you multiply the numerator by 21 to work out what 21 times the fraction is:
13*21/3 = 273/3
Then you can divide 273 by 3 to get the final answer:
273/3 = 91
He will have 91 peaches overall.
Hope this helps! :)
Answer:
y=32x-32
Step-by-step explanation:
this time no algorithm or equation was needed i saw that if the equation was y=32x there would be ordered pairs (1,32) and (2,64) so to delay it by 1 on the x side just subtract the slope from the y - intercept sorry if that doesn't make sense
Whats the topic that you want me to tell about
Let
s-------> <span>represent the number of sheep
g-------> </span><span>represent the number of goats
we know that
1) </span><span>Morgan moves no more than 26 of her sheep and goats into another field
so
(s+g) </span><span>≤ 26------> inequality 1
2) </span><span>Fewer than 14 of her animals are sheep
so
s < 14-------> inequality 2
therefore
the answers are
</span><span>B.) s < 14
</span><span>D.) s + g ≤ 26</span>
