Simplify
1 answer:
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Answer: 3 x 7
Explanation:
So the question is asking you to multiply two prime numbers in order to get 21.
Since 3 and 7 are both prime numbers, you can express 21 as 3 x 7
Hope this helps! :)
Here is a list of prime numbers if it helps you. (prime numbers are in blue):
Explanation:
So the question is asking you to multiply two prime numbers in order to get 21.
Since 3 and 7 are both prime numbers, you can express 21 as 3 x 7
Hope this helps! :)
Here is a list of prime numbers if it helps you. (prime numbers are in blue):
To solve this, set up a proportion, crossmultiply, and solve for x.
Let x = the unknown amount of cases in 60 minutes.
44x = 50(60)
44x = 3000
Divide both sides by 44 to isolate variable x
x = 3000 / 44
x ≈ 68.1818 (the 18s repeat forever)
Rounding to the closest case and assuming the rate stays constant, you would get approximately 68 cases in 60 minutes. If you need not round to the nearest case, you would get approximately 68.18 cases in 60 minutes.
Let x = the unknown amount of cases in 60 minutes.
44x = 50(60)
44x = 3000
Divide both sides by 44 to isolate variable x
x = 3000 / 44
x ≈ 68.1818 (the 18s repeat forever)
Rounding to the closest case and assuming the rate stays constant, you would get approximately 68 cases in 60 minutes. If you need not round to the nearest case, you would get approximately 68.18 cases in 60 minutes.
The group paid $ 5250 at first city and $ 6250 at second city
<u>Solution:</u>
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
The hotel charge before tax in the second city was $1000 higher than in the first
Then the charge at the second hotel before tax will be x + 1000
y = x + 1000 ----- eqn 1
The tax in the first city was 8.5% and the tax in the second city was 5.5%
The total hotel tax paid for the two cities was $790
<em><u>Therefore, a equation is framed as:</u></em>
8.5 % of x + 5.5 % of y = 790
0.085x + 0.055y = 790 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.085x + 0.055(x + 1000) = 790
0.085x + 0.055x + 55 = 790
0.14x = 790 - 55
0.14x = 735
<h3>x = 5250</h3><em><u>Substitute x = 5250 in eqn 1</u></em>
y = 5250 + 1000
<h3>y = 6250</h3>Thus the group paid $ 5250 at first city and $ 6250 at second city