Question

What is an equation of the line that passes through the points (-8, 1) and(7,1)?

Answer 1

Answer:

y=1

Step-by-step explanation:

you can use those points to find the slope

use the equation $\frac{y_{1} - y_{2}}{x_{1}-x_{2}}$ then plug in the numbers

so (1-1)/(-8-7) = 0/15 so the slope is zero meaning it is a horizontal line which we can tell logically because the y coordinates of both points are 1.

so if you plug those numbers into the formula y=mx+b where m is slope and b is the y intercept then

you get y=0*x+1

then 0*x is just zero and it goes away so the equation for this line is y=1

Hope this helps! :)

Answer 2

Step-by-step explanation:

soln;

A(-8,1) = X1,Y1

B(7,1) = X2,Y2

now,

equation of circle ;

(X-X1) (X-X2) + (Y-Y1) (Y-Y2) =0

(x+8) (x-7) + (y-1) (y-1) = 0

x^2-7x+8x-56+y^2-y-y+1 = 0

x^2+y^2+x-2y-55 = 0 is the required equation