Answer:
4c + 6a < = 120 ...4(20) + 6(6) = 116 <== correct
Step-by-step explanation:
Answer:
377 choices
Step-by-step explanation:
From the above question, we are told that
A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.
Let us represent each choice by :
A = Appetizer = 6
M = Main meal = 8
D = Dessert = 5
a) The combination of the 3 choices together
AMD=6 × 8 × 5=240
b) AM= Appetizer and Main meal
= 6 × 8 = 48
c) AD= Appetizer and Dessert
= 6 × 5 = 30
d) MD = Main meal × Dessert
= 8 × 5 = 40
e) A,M,D (each alone)=
Appetizer + Main meal + Dessert
= 6 + 8 + 5
= 19
Assuming all choices are available, how many different possible meals does the restaurant offer?
This is calculated as:
AMD + AM + AD + MD + A,M,D
240 + 48 + 30 + 40 + 19
= 377 choices
By our very goofy system the circle constant
denotes half a circle,
. So the conversion factor from radians to degrees is

Calling the rightmost dot [1] and counting counterclockwise, that's dot [4].

That's dot [6]

That's dot [12]

That's dot [14]
Answer:
x=1/2; y=-6
Step-by-step explanation:
2x-2=-2x-5
4x=2
x=1/2
y=-1-5
y=-6