" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google
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Answer:
C. 3√2 units
Step-by-step explanation:
The diagonal of a square is √2 times the side length. For a square with side length 3, the diagonal is 3√2.
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If you like, you can see this using the Pythagorean theorem.
d² = s² + s² . . . . . where d is the diagonal, and s is the side
d² = 2s²
d = √(2s²) = s√2
For s=3, ...
d = 3√2
Standard Form would be 0.00807
Step-by-step explanation:
THANKS!! FOR THE POINTS