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Gala2k [10]
3 years ago
8

Find a power series representation for the function. (Give your power series representation centered at x=0 .) f(x)=15+x

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

f(x) = \sum\limits^{\infty}_{n=0} \frac{-(1)^n\cdot x^n}{5^{n+1}}

Step-by-step explanation:

Given

f(x) = \frac{1}{5 + x}

Required

The power series centered at x = 0

We have:

f(x) = \frac{1}{5 + x}

Factor out 5 from the denominator

f(x) = \frac{1}{5(1 + \frac{x}{5})}

Rewrite as:

f(x) = \frac{\frac{1}{5}}{(1 + \frac{x}{5})}

Further, rewrite as:

f(x) = \frac{1}{5}(1 + \frac{x}{5})^{-1}

Expand the bracket

f(x) = \frac{1}{5}(1 - \frac{x}{5} + (\frac{x}{5})^2 - (\frac{x}{5})^3+..........)

Evaluate all exponents

f(x) = \frac{1}{5}(1 - \frac{x}{5} + \frac{x^2}{25} - \frac{x^3}{125}+......)

Open brackets

f(x) = \frac{1}{5} - \frac{x}{5^2} + \frac{x^2}{5^3} - \frac{x^3}{5^4}+......

Notice the pattern as:

f(x) = \frac{1}{5} - \frac{x}{5^2} + \frac{x^2}{5^3} - \frac{x^3}{5^4}+......\± \frac{x^n}{5^{n+1}}

So, the power series is:

f(x) = \sum\limits^{\infty}_{n=0} \frac{-(1)^n\cdot x^n}{5^{n+1}}

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3 years ago
Consider the equations 15x + 9y = 45 and 9x + 8y = 12. Solve the system of equations using elimination. Give your solution to th
True [87]

Answer:

(-5.77, 6.46)

Step-by-step explanation:

15x + 9y = 45 ----------- i

9x + 8y = 12----------------ii

Multiply equation i by 9 the coefficient of x in equ ii

And equation ii by 15 the coefficient of x in equ I

9 x 15x + 9y = 45 ----------- i

15 x 9x + 8y = 12----------------ii

135x+81y = 405

135x+120y= 180

Subtract equation ii from I

135x-135x+81y-(+120y)= 405-180

-39y=225

y = 225/-39 = -5.77

Insert the value of y in equ i

15x + 9y = 45

15x+9(-5.77) = 45

15x-51.92=45

15x = 45+51.92

15x= 96.92

x = 96.92/15= 6.46

(x,y) = (-5.77, 6.46)

x = 6.92/15

5 0
3 years ago
I NEED HELP !!!<br> What multiples to make 63 and Adds to make 19?
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Answer:

4.27985 and 14.72015

Step-by-step explanation:

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Answer:

x= 7

Step-by-step explanation:

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Distribute into the parenthesis.

8+4= 2x-2

Now, add.

12= 2x-2

Add 2 to both sides.

12= 2x-2

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Then, divide by 2 to both sides to isolate the variable.

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