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Gala2k [10]
3 years ago
8

Find a power series representation for the function. (Give your power series representation centered at x=0 .) f(x)=15+x

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

f(x) = \sum\limits^{\infty}_{n=0} \frac{-(1)^n\cdot x^n}{5^{n+1}}

Step-by-step explanation:

Given

f(x) = \frac{1}{5 + x}

Required

The power series centered at x = 0

We have:

f(x) = \frac{1}{5 + x}

Factor out 5 from the denominator

f(x) = \frac{1}{5(1 + \frac{x}{5})}

Rewrite as:

f(x) = \frac{\frac{1}{5}}{(1 + \frac{x}{5})}

Further, rewrite as:

f(x) = \frac{1}{5}(1 + \frac{x}{5})^{-1}

Expand the bracket

f(x) = \frac{1}{5}(1 - \frac{x}{5} + (\frac{x}{5})^2 - (\frac{x}{5})^3+..........)

Evaluate all exponents

f(x) = \frac{1}{5}(1 - \frac{x}{5} + \frac{x^2}{25} - \frac{x^3}{125}+......)

Open brackets

f(x) = \frac{1}{5} - \frac{x}{5^2} + \frac{x^2}{5^3} - \frac{x^3}{5^4}+......

Notice the pattern as:

f(x) = \frac{1}{5} - \frac{x}{5^2} + \frac{x^2}{5^3} - \frac{x^3}{5^4}+......\± \frac{x^n}{5^{n+1}}

So, the power series is:

f(x) = \sum\limits^{\infty}_{n=0} \frac{-(1)^n\cdot x^n}{5^{n+1}}

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