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olga nikolaevna [1]
3 years ago
5

Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep

endent consistent and dependent consistent and independent inconsistent and independent
Mathematics
1 answer:
Viktor [21]3 years ago
6 0

<u>Answer:</u>

Consistent and dependent

<u>Step-by-step explanation:</u>

We are given the following equation:

1. 3x+6y-12z=36

2. x+2y-4z=12

3. 4x+8y-16z=48

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with x+2y-4z=12 which is the same as the equation number 2.

There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.

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Harry took a loan from the bank.
Pie

Answer:

The size of Harry's loan is $9000.

Step-by-step explanation:

D(t) models Harry's remaining debt, in dollars, as a function of time t, in months  that is given by :

D(t) =-200t+ 9000

We can see 200 is in negative that means it is getting deducted from the function. So, Harry must be paying this each month against his loan.

Lets put t = 0, that shows no payments have been made.

This will get the amount of loan, before any payments.

D(t)=-200(0)+9000

So,D(t) =9000

Hence, the size of Harry's loan is $9000.

6 0
3 years ago
Answer my math question I asked so many times I lost most of points
maks197457 [2]

Answer:

f(x) = (x+1)^2 - 9

7 0
2 years ago
Read 2 more answers
10 more than 2 times a number is equal to 2 times the number plus 50. What is the number?
PSYCHO15rus [73]

Answer:

y = 40 is the answer

Step-by-step explanation:

Let the number be y

10 more than 2 times a number = 10 + 2×y

equal to 2 times the number plus 50. = 2 × y + 50

10 + 2y = 2y + 50

combine the like terms

2y - 2y =50 - 10

0 = 40

the number supposes be 40 but the number is represented by 0

i think some thing is missing in your question

y supposes be 40 not 0 = 40

Hope this helps!

3 0
3 years ago
Roma sherry drove 80 miles from her home town to her​ parents' town. during her return​ trip, she was able to increase her speed
mr_godi [17]
<span>Answer: Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home. : Let s = original speed then (s+11) = return speed : Write a time equation: Time = distance%2Fspeed : Original time = return time + 1 hr 330%2Fs = 330%2F%28%28s%2B11%29%29 + 1 : Multiply equation by s(s+11) and you have: 330(s+11) = 330s + s(s+11) : 330s + 3630 = 330s + s^2 + 11s : 0 = 330s - 330s + s^2 + 11s - 3630 : A quadratic equation: s^2 + 11s - 3630 = 0 Factor this to: (s + 66)(s - 55) = 0 Positive solution s = 55 mph is original speed. : Find the time 330/55 = 6 hr, original time and 330/66 = 5 hrs, faster time; confirms our solution.</span>
7 0
3 years ago
Which expressions are equivalent??
Brilliant_brown [7]

<u>Given</u>:

The given expression is 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)

We need to determine the equivalent expression.

<u>Option A:</u> -1

Solving the expression, we get;

\frac{3}{2} x+14-\frac{3}{2} x+15

Simplifying, we get;

14+15=29

Thus, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is not equivalent to -1.

Hence, Option A is not the correct answer.

<u>Option B</u>: 29

Solving the expression, we get;

\frac{3}{2} x+14-\frac{3}{2} x+15

Simplifying, we get;

14+15=29

Thus, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent to 29.

Hence, Option B is the correct answer.

<u>Option C</u>: 2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Let us rewrite the given expression.

2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Thus, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent to 2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Thus, Option C is the correct answer.

<u>Option D</u>: 2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)

Rewriting the expression, we get;

2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]

Hence, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent not to 2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)

Thus, Option D is not the correct answer.

<u>Option E:</u> 2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)

Multiplying the terms within the bracket, we get;

2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)

Hence, the expression 2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right) is equivalent to 2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)

Thus, Option E is the correct answer.

4 0
3 years ago
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