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Ugo [173]
3 years ago
6

Which faces have an area of 28in squared

Mathematics
1 answer:
jeyben [28]3 years ago
3 0
To find area, multiply the length by the width
 
So, the very bottom box with a width of 4 in and a length of 7 inches, that equals an area of 28 in 

Also, the very middle box as well

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Given the linear equation 2x+y=6, perform the necessary operations to put the equation into the proper general form. Include the
e-lub [12.9K]

Answer:

y = -2x + 6

Step-by-step explanation:

2x + y = 6

Subtract 2x both sides

2x + y - 2x = 6 - 2x

y = -2x + 6

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32a^6b^5 <br> 26a^2b^4 <br> greatest common factor
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2a^2b^4

Step-by-step explanation:

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In ΔABC (m∠C = 90°), the points D and E are the points where the angle bisectors of ∠A and ∠B intersect respectively sides BC an
Airida [17]

This is a little long, but it gets you there.

  1. ΔEBH ≅ ΔEBC . . . . HA theorem
  2. EH ≅ EC . . . . . . . . . CPCTC
  3. ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
  4. ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
  5. ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
  6. ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
  7. ΔDAC ≅ ΔDAG . . . HA theorem
  8. DC ≅ DG . . . . . . . . . CPCTC
  9. ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
  10. ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
  11. ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
  12. ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
  13. (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
  14. ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
  15. This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
5 0
3 years ago
What isa the area of the square whoose sides mesure 3x + 4​
olga nikolaevna [1]

Answer:

9^{2} + 24x + 16

Step-by-step explanation:

If it is a square, all sides are equal. An area of a square would be side x side. You would multiply 3x + 4 and 3x + 4 together. I used the foil method (multiply first, then outside, inside, last) or (3x * 3x, 3x * 4, 4 * 3x, 4 * 4).

6 0
3 years ago
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