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Inessa [10]
3 years ago
7

David bought a computer than was 20% off the regular price of $ 1,080. if an 8% sales tax was added to the cost of the computer,

what was the total price David paid for it?????
Mathematics
1 answer:
Ne4ueva [31]3 years ago
7 0

Answer:

the anwser would be $933.12

Step-by-step explanation:

1080*.2= 216, so $216 was taken off

1080-216= 864 is the price now

864*.08= 69.12, The sales tax is $69.12

864+69.12= $933.12

The total price David paid for is $933.12

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Step-by-step explanation:

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Rearrange the equation so a is the independent variable. -3a+6b=a+4b, b=
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Answer:

Step-by-step explanation:

Given that

-3a+6b=a+4b

We want to make b subject of formula

First to remove the 4b in the Right hand side of the equation

Subtract 4b from both side of the equation

-3a+6b-4b=a+4b-4b

Then we have,

-3a+2b=a

Now to remove the -3a from the left hand side of the equation add 3a to both side

Then,

-3a+2b+3a=a+3a

2b-3a+3a=4a

Then, 2b=4a

Divide both side by 2

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Maths!
Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

              X                     X-\bar X                   (X-\bar X)^{2}

              5                   5 - 8 = -3                     9

              5                   5 - 8 = -3                     9

              8                   8 - 8 = 0                      0

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

              9                   9 - 8 = 1                       1

              9                   9 - 8 = 1                       1

         <u>     6     </u>              6 - 8 = -2             <u>        4       </u>          

Total <u>    72     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{72}{9}  = 8

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                        =  \sqrt{4.5} = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

              X                     X-\bar X                   (X-\bar X)^{2}

              7                   7 - 10 = -3                     9

              7                   7 - 10 = -3                     9

             10                  10 - 10 = 0                     0

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

              11                  11 - 10 = 1                       1

              11                  11 - 10 = 1                       1

         <u>     8     </u>              8 - 10 = -2             <u>        4       </u>          

Total <u>    90     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{90}{9}  = 10

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the new standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                                =  \sqrt{4.5} = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged as we see in the case of variance or standard deviation.

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