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Marat540 [252]
3 years ago
12

Find the solution of "X" Please: 3(−3−3x)+4=−5

Mathematics
2 answers:
Kaylis [27]3 years ago
6 0

Answer:

x=0

Step-by-step explanation:

3(-3-3x)+4=-5

-9-9x+4=-5

-5-9x=-5

-9x=0

x=0

Lesechka [4]3 years ago
4 0

Answer:

infinite

Step-by-step explanation:

1. -9-9x+4=-5

2. x=0/-9

3. x = infinite

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Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (
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Answer:

a) P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

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The reason is because we don't satisfy the following relationship:

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We have that:

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c) False

In order to satisfy independence we need to have the following condition:

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And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

Step-by-step explanation:

For this case we have the following probabilities given:

P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9

Part a

We want to calculate the following probability: P(A \cap B)

And we can use the total probability rule given by:

P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

Part b

False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

Part c

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P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

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