The mass of the gold bar is = 13.896 kg.
To acheive this answer you have to multiply the area of the trapezium and the length of the bar. Hope this helped x :)
Answer:
Height = 3v/y² units
StartFraction 3 V Over y squared EndFraction units
Step-by-step explanation:
The volume of a solid right pyramid with a square base is v units3 and the length of the base edge is y units. which expression represents the height of the pyramid? units (3v – y2) units (v – 3y2) units units
Volume of a solid right pyramid = 1/3 × area of the base × height
Volume of a solid right pyramid = v units³
Area of the base = y² unit²
Volume of a solid right pyramid = 1/3 × area of the base × height
v = 1/3 × y² × height
Height = v ÷ 1/3 × y²
= v × 3/1y²
= (v × 3) / y²
= 3v / y²
Height = 3v/y² units
StartFraction 3 V Over y squared EndFraction units
3/5 * 230 = 138 votes for Nyemi
3/10 * 230 = 69 votes for Luke
1/10 * 230 = 23 votes for Natalie
***************** DOUBLE-CHECK ****************
138 + 69 + 23 = 230 Correct!!
Answer:
It looks right to me
Step-by-step explanation:
