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Georgia [21]
3 years ago
9

Is 7/3 a rational number ?

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer:Yes 7/3 is a rational number

Step-by-step explanation:

Yes, 7/3 is a rational number. In order to be a rational number, a number must be able to be expressed in the form p/q with both the numerator and the denominator in the fraction are integers.

boyakko [2]3 years ago
4 0

Answer: Yes

Step-by-step explanation: To determine whether 7/3 is a rational number, remember all fractions either positive or negative are rational numbers.

Therefore, 7/3 is a rational number.

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Write an eqution to the table.<br> y x<br> 3 1<br> 1.5 2<br> 1 3
hram777 [196]

Answer:

f(x)=0.5x^2-3x+5.5

Step-by-step explanation:

We can see by some observation that this is not linear because the slopes aren't constant.

So, let's see if it's quadratic. Suppose that it is and the function we want to find is: f(x)=ax^2+bx+c

Plug in some of the given values into the equation:

3 = a + b + c               ------------ eq 1

1 = 9a + 3b + c           ------------ eq 2

1.5 = 4a + 2b + c        ------------ eq 3

Let's multiply eq 3 by 2 and then subtract it from equation 2:

   1 =  9a + 3b + c

-  3 = 8a + 4b + 2c

----------------------------

  -2 = a - b - c

Now, add this equation to eq 1:

   -2 = a - b - c

+   3 = a + b + c

-----------------------

    1 = 2a

    a = 1/2 = 0.5

Now, plug this value of a back into both eq 3 and eq 1:

Eq 3: 1.5 = 4 * 0.5 + 2b + c  ⇒  1.5 = 2 + 2b + c  ⇒  -0.5 = 2b + c     ----- eq 5

Eq 1: 3 = 0.5 + b + c  ⇒  b + c = 2.5   ------ eq 4

So, we have a system of linear equations. Subtract eq 4 from eq 5:

    2b + c = -0.5

-      b + c = 2.5

-------------------------

      b = -3

Substitute this value of b into b + c = 2.5 and solve for c:

-3 + c = 2.5

c = 5.5

So, a = 0.5, b = -3, and c = 5.5. Now, our equation is:

f(x)=0.5x^2-3x+5.5

Hope this helps!

5 0
4 years ago
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ASAP HELP HELP HELP <br><br> i j need to find the cos NO LINKS
Tema [17]

Answer:

Step-by-step explanation:

Hyp = √(3² + √34²) = √43

cosR = adj/hyp = 3/√43

7 0
3 years ago
What is the solution to the linear equation -6z + 1 = 13?
worty [1.4K]
-6z=12
z=-2
choose D
that's it
6 0
4 years ago
Read 2 more answers
Please help me if you get it right i will give you
Inessa [10]
12 + 42 is 54. If you take the numbers apart and add them into tens. 42 because 4 10s and your left with 2 ones. If you take 12 and seperate it into tens you get 1 ten with a remainder of 2. 10 + 10 + 10 + 10 + 10 = 50. 2+2 is 4. Remember that they are the same number so 50 + 4 is 54.
6 0
3 years ago
Read 2 more answers
Bt= 8500 *(8/27)^t/3After a special medicine is introduced into a Petri dish full of bacteria, the number of bacteria remaining
ozzi

Answer:

Every 1.71 seconds, the bacteria loses \frac{1}{2}

Step-by-step explanation:

Given

B(t) = 8500 * (\frac{8}{27})^\frac{t}{3}\\

Required [Missing from the question]

Every __ seconds, the bacteria loses \frac{1}{2}

First, we model the function from t/3 to t.

B(t) = 8500 * (\frac{8}{27})^\frac{t}{3}\\

Apply law of indices

B(t) = 8500 * (\frac{8^\frac{1}{3}}{27^\frac{1}{3}})^t

Evaluate each exponent

B(t) = 8500 * (\frac{2}{3})^t --- This gives the number of bacteria at time t

At time 0, we have:

B(0) = 8500 * (\frac{2}{3})^0

B(0) = 8500 * 1

B(0) = 8500

Let r be the time 1/2 disappears.

When 1/2 disappears, we have:

B(r) = \frac{B(0)}{2}

B(r) = \frac{8500}{2}

B(r) = 4250

So, we have:

B(t) = 8500 * (\frac{2}{3})^t

Substitute r for t

B(r) = 8500 * (\frac{2}{3})^r

Substitute B(r) = 4250

4250 = 8500 * (\frac{2}{3})^r

Divide both sides by 8500

\frac{4250}{8500} =  (\frac{2}{3})^r

\frac{1}{2} =  (\frac{2}{3})^r

Take log of both sides

log(\frac{1}{2}) = log (\frac{2}{3})^r

Apply law of logarithm

log(\frac{1}{2}) = r\ log (\frac{2}{3})

Make r the subject

r = log(\frac{1}{2}) / log (\frac{2}{3})

r = \frac{-0.3010}{-0.1761}

r = 1.71

<em>Hence, it reduces by 1/2 after every 1.71 seconds</em>

6 0
3 years ago
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