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cricket20 [7]
2 years ago
14

A baby pool is shaped like a short, wide cylinder and holds 37 ft3 of water. A medium pool measures 3 times the height and width

of the baby pool. How much water will the medium pool hold?
A. 870 ft3
B. 999 ft3
C. 1036 ft3
D. 1107 ft3
Mathematics
1 answer:
Darya [45]2 years ago
6 0

To solve this problem you must apply the proccedure shown below:

1. You have that the baby pool holds 37ft^{3} and the medium pool measures three times the height and width of the baby pool and both have the shape of a cylinder. Then, you can use the formula for calculate the volume of a cylinder, which is:

V=\pi r^{2} h

Where r is the radius (the half of the width), and h is the height.

2. As the height and the width of the medium pool measure three times the height and width of the baby pool, you must multiply the radius and the heigh by 3, therefore, the volume of the medium pool (V2) is :

V2=\pi (3r)^{2} (3h)\\V2=27\pi r^{2} h\\ V2= 27V1\\ V2=999ft^{3}

The answer is: B. 999ft^{3}

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The rate at which she travels is given by

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2 years ago
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3 years ago
Graph the line with slope – 2 passing through the point (-5,5).
34kurt

Answer:

y = -2x - 5

Step-by-step explanation:

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- To find the y-intercept, plug the values of the variables.

5 = -2(-5) + b

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3 0
2 years ago
A certain article reported the following observations, listed in increasing order, on drill lifetime (number of holes that a dri
aleksklad [387]

Answer:

Sample mean =119.42

Median = 92

25% trimmed mean = 102.42

10% trimmed mean = 95.69

Step-by-step explanation:

Data in increasing order :

12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513

Total no. of observations = 50

Sample mean = \frac{\text{Sum of all observations}}{\text{Total number of observations}}

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Median = \frac{1}{2}({25\text{th term} + 26\text{th term}) = \frac{91+93}{2} = 92

10% Trimmed Mean: We remove 5 values from each side

Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{4097}{40} = 102.42

25% Trimmed Mean: We remove 12 values from each side.

Trimmed set =  66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{2488}{26} = 95.69

6 0
3 years ago
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