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cricket20 [7]
3 years ago
14

A baby pool is shaped like a short, wide cylinder and holds 37 ft3 of water. A medium pool measures 3 times the height and width

of the baby pool. How much water will the medium pool hold?
A. 870 ft3
B. 999 ft3
C. 1036 ft3
D. 1107 ft3
Mathematics
1 answer:
Darya [45]3 years ago
6 0

To solve this problem you must apply the proccedure shown below:

1. You have that the baby pool holds 37ft^{3} and the medium pool measures three times the height and width of the baby pool and both have the shape of a cylinder. Then, you can use the formula for calculate the volume of a cylinder, which is:

V=\pi r^{2} h

Where r is the radius (the half of the width), and h is the height.

2. As the height and the width of the medium pool measure three times the height and width of the baby pool, you must multiply the radius and the heigh by 3, therefore, the volume of the medium pool (V2) is :

V2=\pi (3r)^{2} (3h)\\V2=27\pi r^{2} h\\ V2= 27V1\\ V2=999ft^{3}

The answer is: B. 999ft^{3}

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The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.10
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For the bell-shaped graph of the normal distribution of weights of Hershey kisses, the area under the curve is 1, the value of the median and mode both is 4.5338 G and the value of variance is 0.0108.

In the given question,

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From the question;

Mean(μ) = 4.5338 G

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(a) We have to find for the bell-shaped graph of the normal distribution of weights of Hershey kisses what is the area under the curve.

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To learn more about normally distribution link is here

brainly.com/question/15103234

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Step-by-step explanation:

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