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cricket20 [7]
2 years ago
14

A baby pool is shaped like a short, wide cylinder and holds 37 ft3 of water. A medium pool measures 3 times the height and width

of the baby pool. How much water will the medium pool hold?
A. 870 ft3
B. 999 ft3
C. 1036 ft3
D. 1107 ft3
Mathematics
1 answer:
Darya [45]2 years ago
6 0

To solve this problem you must apply the proccedure shown below:

1. You have that the baby pool holds 37ft^{3} and the medium pool measures three times the height and width of the baby pool and both have the shape of a cylinder. Then, you can use the formula for calculate the volume of a cylinder, which is:

V=\pi r^{2} h

Where r is the radius (the half of the width), and h is the height.

2. As the height and the width of the medium pool measure three times the height and width of the baby pool, you must multiply the radius and the heigh by 3, therefore, the volume of the medium pool (V2) is :

V2=\pi (3r)^{2} (3h)\\V2=27\pi r^{2} h\\ V2= 27V1\\ V2=999ft^{3}

The answer is: B. 999ft^{3}

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Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

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2 years ago
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3 years ago
Round Ed to the nearthest tenth and answer now question
Vikki [24]

Answer:

y = 9.1

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y can be found using the Law of sines as explained below:

m < Y = 106°

m < X = 58°

WY = x = 8

WX = y = ?

Thus,

\frac{x}{sin(X)} = \frac{y}{sin(Y)}

\frac{8}{sin(58)} = \frac{y}{sin(106)}

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Multiply both sides by 0.961 to solve for y

\frac{8}{0.848}*0.961 = \frac{y}{0.961}*0.961

\frac{8*0.961}{0.848} = y

\frac{8*0.961}{0.848}*0.961 = y

9.07 = y

y = 9.1 (to the nearest tenth)

7 0
3 years ago
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