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katrin [286]
3 years ago
8

Team A is located on the south bank of a river. Teams B and C are located on the north bank. The angle formed from Team C to Tea

m A is S 42o W. Team C is 10 feet due east of Team B and 12 feet from Team A. How far is Team A from Team B?
8.1 ft

12.4 ft

20.6 ft

9.1 ft
Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
20 Ft is the answer
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How would you solve this without a calculator?
Soloha48 [4]

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Exact Form:

1351+780\sqrt{3}

Decimal Form:

2701.99962990

Thus, <em>2,701</em> is your answer

5 0
2 years ago
A company makes a $5 profit on each non-faulty product it sells. approximately 2% of the products manufactured are faulty, with
aivan3 [116]
We are given with a company profit of $ 5 profit where 2% of the products are faulty and the replacement-and-repait costs for the fauly products are equivalent to $ 100 each. Due to these faulty products, the equation becomes $ 5/ 1 = $ x / 0.98. The proft per item then is $ 4.9. 
3 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Water runs from a pump at a rate of 0.5 gallons per minute. At this rate, how long would it take to fill a tub with a 150-gallon
lutik1710 [3]

Answer:

300 min or 5 hours

Step-by-step explanation:

so if it pumps 0.5 gallons per minute than in 2 minutes it would pump 1 whole gallon so with that we know 1gallon=2 minutes.

so with that we multipy both sides by 150 which will be 150 galons=300 minutes or 5 hours

3 0
3 years ago
ASAP WILL GIVE BRAINLIEST!!! DO NOT USE PICTURES PLEASE Part A: Solve the equation 7x + 3x − 18 = 6(x + 3), and show your work.
Brrunno [24]
The answer is x=9 because (look at the picture)

7 0
3 years ago
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