Answer:
D. ![\left[\begin{array}{ccc}-12&-4\\9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%26-4%5C%5C9%263%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In order for a matrix to be singular, the determinant has to be zero.
It is x * y * z for a little hint
Answer:
f(-1) = 6
Step-by-step explanation:
f(x) = x + 7 when x = -1
~Substitute
= (-1) + 7
~Simplify
= 6
Best of Luck!
Answer:
The value of car after 14 years is $ 2,363.04
Step-by-step explanation:
Given as :
The price of new car = N = $ 18,000
The rate of depreciation of the value of the car = R = 13.5 % per year
Let The value of car after 14 years = $ x
The time period = 14 years
<u>Now, According to question</u>
The value of car after n years = initial value of car × 
or, $ x = N × 
or, $ x = $ 18,000 × 
Or, $ x = $ 18,000 × 
∴ x = $ 18,000 × 0.13128
I.e x = $ 2,363.04
So, The value of car after 14 years = x = $ 2,363.04
Hence The value of car after 14 years is $ 2,363.04 Answer