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Greeley [361]
3 years ago
12

One side of a rectangle is three times the other. Find the longer side if the perimeter is 29

Mathematics
2 answers:
Sveta_85 [38]3 years ago
4 0

Answer:

Answer:10.875

Step-by-step explanation:

Let the short side be x.

Then the long side is 3x.

There are two opposite sides of each length, so the perimeter is

3x + 3x + x + x = 8x

The perimeter is 29, so we get the equation

8x = 29

Solve for x by dividing both sides by 8.

x = 29/8

x = 3.625

The longer side is 3x.

3x = 3(3.625) = 10.875

Answer: 10.875

Read more on Brainly.com - brainly.com/question/16234897#readmore

guajiro [1.7K]3 years ago
3 0

Answer:

Answer: 10.875

Step-by-step explanation:

Let the short side be x.

Then the long side is 3x.

There are two opposite sides of each length, so the perimeter is

3x + 3x + x + x = 8x

The perimeter is 29, so we get the equation

8x = 29

Solve for x by dividing both sides by 8.

x = 29/8

x = 3.625

The longer side is 3x.

3x = 3(3.625) = 10.875

Answer: 10.875

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3 years ago
You have quarters and dimes that total $2.80. your friend says it is possible that the number of quarters is 8 more than the num
ss7ja [257]
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D

The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.  
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
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