Find the exact interest on a loan of $32,600 at 9% annually for 30 days

if a distribution of raw scores were plotted and then the scores were transformed to z scores, would the shape of the distributi

nadya68 [22]

•If the raw score is transformed into a z-score, however, the value of the z-score tells exactly where the score is located relative to all the other scores in the distribution.

3 0

2 years ago

For questions 1 – 6, find the area of the circle to the nearest hundredth. Any help appriciated!

Ganezh [65]

Step-by-step explanation:

The area of a circle is given by :

A = πr²

r is the radius of the circle

(4) Diameter = 22 cm

Since, radius = diameter/2

r = 11 cm

Now, area of the circle,

$A=\pi \times (11)^2\\\\A=380.13\ cm^2$

(5) Diameter = 30 cm

Since, radius = diameter/2

r = 15 cm

Now, area of the circle,

$A=\pi \times (15)^2\\\\A=706.85\ cm^2$

(6) Diameter = 4cm

Since, radius = diameter/2

r = 2 cm

Now, area of the circle,

$A=\pi \times (2)^2\\\\A=12.56\ cm^2$

So, the area of circles 4,5 and 6 are 380.13², 706.85² and 12.56² respectively.

4 0

2 years ago

What is mean in math

PSYCHO15rus [73]

The mean is the average of the numbers. to find the mean add up the numbers and divide by how many numbers there are

6 0

2 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by: