Click on the second choice, the 3x one
Answer:
Triangle APB is an isosceles triangle ⇒ 3rd answer
Step-by-step explanation:
* Lets explain the how to solve the problem
- ABCD is a square
∴ AB = BC = CD = AD
∴ m∠A = m∠∠B = m∠C = m∠D = 90°
- DPC is equilateral triangle
∴ DP = PC = DC
∴ m∠DPC = m∠PCD = m∠CDP = 60°
- In the Δs APD , BPC
∵ AD = BC ⇒ sides of the square
∵ PD = PC ⇒ sides of equilateral triangle
∵ m∠ADB = m∠BCP = 30° (90° - 60° = 30) ⇒ including angles
∴ Δs APD , BPC are congregant ⇒ SAS
- From congruent
∴ AP = BP
∴ Triangle APB is an isosceles triangle
I ussually think of them as arrows telling me where to go.
if it is > you go ----->
if it is < you go <------
Answer:
* * *
|-4|___|-3|___|-2|___|-1|___|0|___|1|___|2|___|3|___|4|___|5|___|6|
Step-by-step explanation:
You are looking for a dot over -2 (that is 2 units to the left of 0).
You are looking for a dot over 3 (that is 3 units to the right of 0).
You are looking for a dot over 4 (that is 4 units to the right of 0).
If you find one of the graphs matches this, then you should select.
The graph would look like this:
* * *
|-4|___|-3|___|-2|___|-1|___|0|___|1|___|2|___|3|___|4|___|5|___|6|
